14th July 2014
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More noise than signal
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Join Date: May 2008
Location: USA
Posts: 7,975
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Quote:
Originally Posted by cravuhaw2C
...how did partition 0 end up with only 27.94 GB (28,609 MB divided by 1024 MB = 27.94 GB) ?
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I only have the information you provided above, in your fdisk report.
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I don't understand how you arrived at 512-byte sectors.
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- Mass storage (a.k.a. "hard drives") that use fixed block architectures use either 512-byte or 4096-byte sector sizes. The vast majority use 512-byte, as 4096 is actually very new.
- You told us your device was 240 GB.
- Your report above shows 468,862,128 sectors. Multiplied by 512, that's 240,057,409,536 bytes.
- Drive manufactures use "marketing" sizes, which is 1,000 for Kilo, 1,000,000 for Mega, 1,000,000,000 for Giga, etc. None have ever used 1,024 for their math.
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Am I right to assume you were referring to partition 2 that corresponds to id #2? If yes, shouldn't I start on Cylinder 9118 and not 9119?
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Cylinder 9118 is in use by partition #1. It ends in the middle of Cylinder 9118, at Head 40 / Sector 10. Starting at the beginning of Cylinder 9118 would cause an overlay between your two partitions.
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Using C/H/S method, shouldn't the starting values be 9118 /40 /11?
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I recommended starting at a cylinder boundary, as I explained above.
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If using LBA method, how did you arrive at sector 146496735?
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Per your report, each cylinder is 16,605 sectors long. I'd recommended starting at the beginning (Head 0 / Sector 1) of the next available cylinder, 9119.
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Your job title at OpenBSD should be "official ambassador".
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Thank you, but I'm not a member of the Project, I'm just a user. And this site is entirely unofficial.
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