OpenBSD find command -- exclude dot directory
How do I tell the OpenBSD find(1) command to exclude the dot directory, but not its contents, from the list of directories and files it generates?
It seems like this should be possible with the not (!) operator, but after searching the Web, reading (and re-reading) the find(1) man page, and trying out numerous combinations of arguments and operators, I still have not found a solution.
Using -prune doesn't work for me in this situation; -prune will cause find to not descend into the pruned directory. If the pruned directory is the dot directory, the contents of the directory will be missing. Effectively, find will generate an empty list. This is obviously not the desired behavior.
I have found ways to exclude:
I've written a sample script to demonstrate the problem because it's easier to see than on the command line.
If, for example, my home directory is the current directory and contains the following items:
and I want the generated list to look like this:
I can run this script to test the find command -- the results are explained in the comments:
#!/bin/sh # findtest cd $HOME # Method 1 works to exclude the dot directory and specified files; # contents of named directories are ignored by find and end up in the printed list. METHOD1='( ! -name . ! -path ./.Xdefaults ! -path ./.cache ! -path ./dirC ! -path ./file4.pdf )' find . $METHOD1 -print | sort > method1.txt # Method 2 works to exclude named directories and specified files; # adding the dot directory to this command results in an empty list. METHOD2='( -path ./.Xdefaults -or -path ./.cache -or -path ./dirC -or -path ./file4.pdf )' find . $METHOD2 -prune -or -print | sort > method2.txt #Method 3 should exclude the dot directory, named directories, and specified files. ## METHOD3=... ## find . $METHOD3...
Any help would be appreciated.
Last edited by gustaf; 11th January 2017 at 09:22 PM. Reason: added link to find(1) man page; corrected comments and code for Method 1
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