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IPV6 addresses how are they written?
Multiple choice quiz:
A) IPV6 addresses are 4 groups of 4 hexadecimal characters separated by colons. B) IPV6 addresses are 6 groups of 4 hexadecimal characters separated by colons. C) IPV6 addresses are 7 groups of 4 hexadecimal characters separated by colons. D) IPV6 addresses are 8 groups of 4 hexadecimal characters separated by colons. If you look at the current version of "Absolute OpenBSD" 2nd Edition (PDF), then page 193 under "IPV6 Basics" says that B) is the correct answer. If you go to the OpenBSD FAQ section 6.1, it suggests reading the "Understanding IP Addressing" by 3COM. http://openbsd.org/faq/faq6.html#Intro http://www.scribd.com/doc/52483921/3...-IP-Addressing And if you look on page 43 of the 3COM document you find "Figure 36: Hexadecimal to Binary Conversion" which clearly shows that C) is the correct answer. However if one looks at either the FreeBSD FAQ or the NetBSD FAQ or Wikipedia then D) is the correct answer. http://www.freebsd.org/doc/en_US.ISO...work-ipv6.html http://www.netbsd.org/docs/guide/en/...tml#ipv6-intro http://en.wikipedia.org/wiki/IPv6 Last edited by comet--berkeley; 6th May 2013 at 11:00 PM. Reason: grammar |
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Quote:
http://en.wikipedia.org/wiki/IPv6_address The IPV6 address 0:0:0:0:0:0:0:0 can be legitimately abbreviated as ::, so can I guess E) none of the above? |
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Quote:
so case D) still holds. Last edited by comet--berkeley; 7th May 2013 at 06:09 AM. Reason: color |
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C'mon guys, do the math. 4 hexidecimal = 16 bits. We all agree that ipv6 addresses are 128 bits in length, so 128/16 = 8.
I don't know if these are typos, but I suspect so, as the hex7-page43 image linked by the OP shows 112 bits, not 128. Seems more an editing fail than an RFC fail.
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Linux/Network-Security Engineer by Profession. OpenBSD user by choice. |
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