How to remove a word and everything after?

[bigb89]

Hi guys,

Here's what I'm trying to do. Let's say I have the following line:

43.96.199.87 Bcast:43.96.199.255 Mask:255.255.255.0

How could I remove the word Bcast and anything after that word so that the line would look like this:

43.96.199.87

Please let me know of way that I can achieve this.

P.S. I really appreciate the help you guys have given me.

[vermaden]

# echo "43.96.199.87 Bcast:43.96.199.255 Mask:255.255.255.0" | awk '{print $1}'

[anemos]

echo 43.96.199.87 Bcast:43.96.199.255 Mask:255.255.255.0 | sed s/"Bcast.*"/""/

[bigb89]

Thank you very much guys!

I was able to do exactly what I needed your help!

[drl]

Hi.

The other side of the coin is to extract a portion of a line. In this case we notice the string is field number 1. We can use another standard command similar to the awk solution:

#!/usr/bin/env bash

# @(#) s1       Demonstrate extraction of field.

echo
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version "=o" $(_eat $0 $1) cut
set -o nounset

echo
s="43.96.199.87 Bcast:43.96.199.255 Mask:255.255.255.0"
echo " Input string: $s"
echo
echo " Results:"
echo "$s" | cut -d" " -f1

exit 0

Producing:

$ ./s1

(Versions displayed with local utility "version")
FreeBSD 4.11-STABLE
GNU bash 3.1.17
cut - no version provided for /usr/bin/cut.

 Input string: 43.96.199.87 Bcast:43.96.199.255 Mask:255.255.255.0

 Results:
43.96.199.87

cheers, drl

[Mike-Sanders]

Another example below as well

echo 43.96.199.87 Bcast:43.96.199.255 Mask:255.255.255.0 | cut -w -f 1

[Carpetsmoker]

While useful, -w is a FreeBSD-specific extension to cut.

[Mike-Sanders]

Was not aware that '-w' was limited to FreeBSD... appreciate the info.